← MathScape

Function Arithmetic

MATH161
Reference: Stewart 1.3  •  Chapter: 1  •  Section: 3

Navigation: Wiki Home > Skills > Function Arithmetic

Function Arithmetic

Building Functions from Building Blocks

You already know how to add numbers. But what does it mean to add two functions? If $f(x) = x^2$ and $g(x) = \sqrt{x}$, what is $(f + g)(x)$?

Function arithmetic lets you combine functions using the same operations you use with numbers: addition, subtraction, multiplication, and division. The key insight is that you're creating a new function whose outputs are computed from the outputs of the original functions.

This skill matters because real-world quantities often depend on multiple factors combined together. Revenue minus cost gives profit. Velocity times time gives distance. Learning to combine functions prepares you for building mathematical models of complex systems.

Prerequisite Map

Prerequisites
Function NotationAlgebraic Operations
This skill
Function Arithmetic

Quick Reference

Property Value
Course MATH 161
Chapter 1.3
Difficulty Beginner
Time ~15 minutes

Key Concepts

The Four Operations

Given two functions $f$ and $g$, we define new functions as follows:

Operation Definition Domain
Sum $(f + g)(x) = f(x) + g(x)$ $\text{dom}(f) \cap \text{dom}(g)$
Difference $(f - g)(x) = f(x) - g(x)$ $\text{dom}(f) \cap \text{dom}(g)$
Product $(fg)(x) = f(x) \cdot g(x)$ $\text{dom}(f) \cap \text{dom}(g)$
Quotient $\left(\frac{f}{g}\right)(x) = \frac{f(x)}{g(x)}$ $\text{dom}(f) \cap \text{dom}(g)$, where $g(x) \neq 0$

The Domain Rule

The domain of a combined function is where BOTH original functions are defined—and for division, the denominator can't be zero.

This is the most important concept in function arithmetic. Think of it as a Venn diagram:

Domain of f:         Domain of g:
   [────────]           [────────]
       ↓                    ↓
       └─────── ∩ ─────────┘
                ↓
         Domain of f ± g, fg
                ↓
         (minus where g = 0 for f/g)

Why Intersection?

To compute $(f + g)(x)$, you need both $f(x)$ and $g(x)$. If either function is undefined at some $x$, the sum is undefined there too.

Example: If $f(x) = \sqrt{x}$ (domain: $x \geq 0$) and $g(x) = \sqrt{4-x}$ (domain: $x \leq 4$), then:

$$\text{dom}(f + g) = [0, \infty) \cap (-\infty, 4] = [0, 4]$$

Common Domain Restrictions

Expression Restriction Reason
$\sqrt{\text{stuff}}$ $\text{stuff} \geq 0$ Can't take square root of negative
$\frac{1}{\text{stuff}}$ $\text{stuff} \neq 0$ Can't divide by zero
$\ln(\text{stuff})$ $\text{stuff} > 0$ Logarithm requires positive input

Working with Combined Functions

When simplifying combined functions:

  1. Write out the definition
  2. Substitute the formulas for $f(x)$ and $g(x)$
  3. Simplify algebraically
  4. State the domain (don't forget restrictions!)

Practice Problems

Level 1 Direct Computation

If $f(x) = 2x + 1$ and $g(x) = x^2$, find $(f + g)(3)$.

Thought Process

Use the definition: $(f + g)(3) = f(3) + g(3)$. Compute each function value separately, then add.

Show Answer

$(f + g)(3) = f(3) + g(3)$

$f(3) = 2(3) + 1 = 7$

$g(3) = 3^2 = 9$

$(f + g)(3) = 7 + 9 = \boxed{16}$

Level 2 Finding a Combined Function Formula

Let $f(x) = x^2 - 1$ and $g(x) = 2x + 3$. Find formulas for:

  1. $(f - g)(x)$
  2. $(fg)(x)$
Thought Process

For each part, substitute the function formulas into the definition. For the difference, subtract the entire expression for $g$. For the product, multiply and expand.

Show Answer

(a) $(f - g)(x) = f(x) - g(x)$ $$= (x^2 - 1) - (2x + 3)$$ $$= x^2 - 1 - 2x - 3$$ $$= \boxed{x^2 - 2x - 4}$$

(b) $(fg)(x) = f(x) \cdot g(x)$ $$= (x^2 - 1)(2x + 3)$$ $$= 2x^3 + 3x^2 - 2x - 3$$ $$= \boxed{2x^3 + 3x^2 - 2x - 3}$$

Level 3 Domain of a Quotient

Let $f(x) = \sqrt{x + 2}$ and $g(x) = x - 1$. Find the domain of $\left(\frac{f}{g}\right)(x)$.

Thought Process

Three restrictions to check:

  1. Domain of $f$: need $x + 2 \geq 0$
  2. Domain of $g$: all reals (polynomial)
  3. Division restriction: need $g(x) \neq 0$

Combine all restrictions using intersection.

Show Answer

Step 1: Domain of $f(x) = \sqrt{x+2}$

Need $x + 2 \geq 0$, so $x \geq -2$.

Step 2: Domain of $g(x) = x - 1$

All real numbers (it's a polynomial).

Step 3: Intersection

$[-2, \infty) \cap \mathbb{R} = [-2, \infty)$

Step 4: Remove where $g(x) = 0$

$g(x) = 0$ when $x = 1$

Final domain: $[-2, 1) \cup (1, \infty)$

Or in interval notation: $\boxed{[-2, 1) \cup (1, \infty)}$

Level 4 Domain with Multiple Restrictions

Let $f(x) = \frac{1}{x-3}$ and $g(x) = \sqrt{x-1}$. Find the domain of $(fg)(x)$ and write a formula for this function.

Thought Process

Both functions have restrictions:

  • $f$: denominator can't be zero, so $x \neq 3$
  • $g$: expression under square root must be non-negative, so $x \geq 1$

Find the intersection of these conditions.

Show Answer

Domain of $f$: $x \neq 3$, i.e., $(-\infty, 3) \cup (3, \infty)$

Domain of $g$: $x \geq 1$, i.e., $[1, \infty)$

Intersection: $$[1, \infty) \cap \left[(-\infty, 3) \cup (3, \infty)\right] = [1, 3) \cup (3, \infty)$$

Formula: $$(fg)(x) = \frac{1}{x-3} \cdot \sqrt{x-1} = \frac{\sqrt{x-1}}{x-3}$$

Domain: $\boxed{[1, 3) \cup (3, \infty)}$

Level 5 Function Arithmetic and Symmetry

Let $f$ be any function with domain symmetric about the origin (i.e., if $x$ is in the domain, so is $-x$).

Define: $$E(x) = \frac{f(x) + f(-x)}{2} \quad \text{and} \quad O(x) = \frac{f(x) - f(-x)}{2}$$

  1. Prove that $E$ is an even function (i.e., $E(-x) = E(x)$).
  2. Prove that $O$ is an odd function (i.e., $O(-x) = -O(x)$).
  3. Verify that $f(x) = E(x) + O(x)$.
  4. Apply this to $f(x) = e^x$. What are $E(x)$ and $O(x)$?
Thought Process

For parts (a) and (b), substitute $-x$ into the formulas and simplify.

For part (c), add the formulas for $E(x)$ and $O(x)$.

For part (d), apply the formulas to $e^x$ and recognize the results as hyperbolic functions.

Show Answer

(a) Prove $E$ is even:

$$E(-x) = \frac{f(-x) + f(-(-x))}{2} = \frac{f(-x) + f(x)}{2} = E(x) \checkmark$$

(b) Prove $O$ is odd:

$$O(-x) = \frac{f(-x) - f(-(-x))}{2} = \frac{f(-x) - f(x)}{2} = -\frac{f(x) - f(-x)}{2} = -O(x) \checkmark$$

(c) Verify $f = E + O$:

$$E(x) + O(x) = \frac{f(x) + f(-x)}{2} + \frac{f(x) - f(-x)}{2} = \frac{2f(x)}{2} = f(x) \checkmark$$

(d) For $f(x) = e^x$:

$$E(x) = \frac{e^x + e^{-x}}{2} = \cosh(x)$$

$$O(x) = \frac{e^x - e^{-x}}{2} = \sinh(x)$$

This is the definition of the hyperbolic cosine and sine functions! Every exponential can be decomposed into its even and odd parts.

Mastery Checklist

Mental Model

The Assembly Line Analogy: Think of $f$ and $g$ as two workers on an assembly line. Each takes an input $x$ and produces an output. To combine their work:

The domain is where BOTH workers can do their job. If either worker can't handle an input, the combined operation fails.


Previous Up Next
Function Transformations Section 1.3 Function Composition

Last updated: 2026-01-22