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Polar Curves

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Reference: Stewart §10.3

Textbook Reference

Primary source OpenStax Calculus Volume 2, Section 7.3: “Polar Coordinates”
Direct link https://openstax.org/books/calculus-volume-2/pages/7-3-polar-coordinates
Textbook used in class Stewart, Calculus, Section 10.3: “Polar Coordinates”

Opening Scenario

The equation $r = 1 + \cos\theta$ describes a heart-shaped curve called a cardioid. The equation $r = \sin(2\theta)$ traces a four-petaled rose. Neither of these has a simple Cartesian form, but they are natural and elegant in polar coordinates. Plotting polar curves requires building a table of $(r, \theta)$ values, then converting to Cartesian points or plotting on a polar grid.


Quick Reference

Graphing $r = f(\theta)$: Choose key values of $\theta$, compute $r$, plot the points $(r,\theta)$ on a polar grid. Connect in order of increasing $\theta$.

Common polar curves:

Curve Equation Description
Circle (centered at origin) $r = a$ Radius $a$
Circle (through origin) $r = 2a\cos\theta$ Center $(a,0)$, radius $a$
Cardioid $r = a(1+\cos\theta)$ Heart shape; passes through origin
Limaon $r = a + b\cos\theta$ Varies by ratio $a/b$
Rose curve $r = a\cos(n\theta)$ $n$ petals if $n$ odd; $2n$ petals if $n$ even
Lemniscate $r^2 = a^2\cos(2\theta)$ Figure-eight curve
Archimedean spiral $r = a\theta$ Spiral expanding from origin

Key Concepts

1. Building a Table for $r = f(\theta)$

Choose $\theta = 0, \pi/6, \pi/4, \pi/3, \pi/2, \pi, 3\pi/2, 2\pi$ (and values where $r = 0$ or $r$ is maximum). Compute $r = f(\theta)$ at each. Plot $(r,\theta)$ on a polar grid or convert to Cartesian $(r\cos\theta, r\sin\theta)$.

When $r < 0$ at some $\theta$, the point is in the direction $\theta + \pi$. These points are still part of the curve.

2. Symmetry Tests

Polar symmetry can be detected before plotting:

Symmetry Test Meaning
About $x$-axis $f(-\theta) = f(\theta)$ (or $f(\pi-\theta) = f(\theta)$) Reflects across $x$-axis
About $y$-axis $f(\pi-\theta) = f(\theta)$ Reflects across $y$-axis
About origin $f(\theta+\pi) = f(\theta)$ or $f(-\theta) = -f(\theta)$ 180-degree rotational symmetry

Warning: The symmetry tests are sufficient but not necessary -- a polar curve can have symmetry even if none of the algebraic tests hold (due to multiple representations of the same point in polar).

3. Key Features of Common Curves

Cardioid $r = a(1+\cos\theta)$:

Rose curve $r = a\cos(n\theta)$:


Worked Example

Sketch the cardioid $r = 1 + \sin\theta$.

Table of values:

$\theta$ $r = 1+\sin\theta$
$0$ 1
$\pi/6$ 1.5
$\pi/2$ 2
$5\pi/6$ 1.5
$\pi$ 1
$3\pi/2$ 0
$2\pi$ 1

Key features:

Description: A heart shape pointing upward (cardioid). It starts at $(1,0)$ on the right, expands to the top at $(0,2)$ in Cartesian coordinates, contracts to the origin at the bottom, and returns to the right. The curve is traced once as $\theta$ goes from $0$ to $2\pi$.


Common Errors Summary

Error Example Correction
Ignoring $r < 0$ points Stopping the curve when $r$ first becomes negative Points with $r < 0$ lie in the direction $\theta + \pi$; they are part of the curve
Plotting $r$ vs. $\theta$ as a Cartesian graph Drawing a sine wave instead of a cardioid $r = 1+\sin\theta$ is plotted on a polar grid, not on $(r,\theta)$ axes
Missing petals of a rose curve Drawing 2 petals of $r = \cos(2\theta)$ instead of 4 For even $n$, $r = a\cos(n\theta)$ has $2n$ petals; trace over $[0,2\pi]$ to capture all of them

Common Misconceptions

Common misconception

the graph of $r = f(\theta)$ is drawn on $(r, \theta)$ axes like a Cartesian graph.

This is the iconic-graph error. The polar equation $r = 1 + \cos\theta$ describes a curve in the plane with the origin at the pole. Plotting $r$ on the vertical axis against $\theta$ on the horizontal axis produces a sine-wave-like picture that is not the cardioid. The correct picture plots each point $(r\cos\theta, r\sin\theta)$ in the plane for the appropriate $\theta$-values.

Common misconception

when $r < 0$ for some $\theta$, those points are not part of the curve.

This is the concept-image-conflicts-definition error. A polar curve is defined by $r = f(\theta)$ for all $\theta$ in the given range, including values where $f(\theta) < 0$. A negative $r$ places the point in the direction $\theta + \pi$. Ignoring those points omits entire petals from rose curves and entire branches from limacons.


Leveled Practice

Level 1 -- Build a Table and Identify

Problem 1. Build a table of values and identify the curve $r = 3\cos\theta$, $0 \leq \theta \leq \pi$.

Show answer
$\theta$ $r = 3\cos\theta$ $(x,y)$
0 3 $(3,0)$
$\pi/3$ 1.5 $(0.75, 1.3)$
$\pi/2$ 0 $(0,0)$
$2\pi/3$ $-1.5$ $(0.75,-1.3)$
$\pi$ $-3$ $(3,0)$

Convert: $x = r\cos\theta = 3\cos^2\theta$, $y = r\sin\theta = 3\cos\theta\sin\theta$.

Cartesian: $x^2+y^2 = r^2 = 3r\cos\theta = 3x$, so $(x-3/2)^2+y^2 = 9/4$. This is a circle of radius $3/2$ centered at $(3/2, 0)$.


Level 2 -- Count Petals

Problem 2. How many petals does $r = \cos(3\theta)$ have, and for which $\theta$-values do the petals occur?

Show answer

$n = 3$ is odd, so $r = \cos(3\theta)$ has $n = 3$ petals.

Petals occur where $r$ is maximum ($r = 1$), i.e., $3\theta = 0, 2\pi, 4\pi$, giving $\theta = 0, 2\pi/3, 4\pi/3$.

The petal tips are at $\theta = 0, 2\pi/3, 4\pi/3$.


Mastery Checklist


Mental Model

A polar curve $r = f(\theta)$ is traced by a radius that rotates counterclockwise from $\theta = 0$. At each angle, the length of the radius is $r = f(\theta)$. As $\theta$ sweeps around, the tip of this rotating radius traces the curve. Where $f(\theta) = 0$, the tip is at the origin. Where $f(\theta)$ is maximum, the tip is farthest from the origin. Symmetry means the curve “mirrors” itself across some axis.


Connections

Looking back

Looking ahead


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