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Three-Dimensional Coordinates

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Reference: Stewart §12.1

Textbook Reference

Primary source OpenStax Calculus Volume 3, Section 2.1: “Vectors in the Plane” and Section 1.1: “Parametric Equations”
Supplementary OpenStax Calculus Volume 3, Section 2.2: “Vectors in Three Dimensions”
Supplementary link https://openstax.org/books/calculus-volume-3/pages/2-2-vectors-in-three-dimensions
Textbook used in class Stewart, Calculus, Section 12.1: “Three-Dimensional Coordinate Systems” (Examples 1, 2)

Opening Scenario

A GPS unit reports your position as latitude, longitude, and altitude: three numbers that locate you in space. The three-dimensional coordinate system is the mathematical version of that idea. Every point in space corresponds to an ordered triple $(x, y, z)$, and two-dimensional geometry -- lines, planes, distances -- extends cleanly into three dimensions.


Quick Reference

The $xyz$-coordinate system. Three mutually perpendicular axes meet at the origin $O = (0, 0, 0)$:

Coordinate planes:

These three planes divide space into eight octants. The first octant has $x > 0$, $y > 0$, $z > 0$.

Planes parallel to coordinate planes: The equation $z = c$ (constant) describes a horizontal plane at height $c$, parallel to the $xy$-plane. Similarly $x = c$ is a plane parallel to the $yz$-plane, and $y = c$ is parallel to the $xz$-plane.


Key Concepts

1. Plotting Points in 3D

To plot $(x_0, y_0, z_0)$: start at the origin, move $x_0$ units along the $x$-axis, then $y_0$ units parallel to the $y$-axis, then $z_0$ units parallel to the $z$-axis.

Example 1. Locate the points $P = (3, -2, 4)$ and $Q = (-1, 0, 2)$. (Stewart 12.1, Example 1.)

For $P$: move $3$ right along $x$, $2$ back along $y$ (since $-2$), and $4$ up along $z$. For $Q$: move $1$ left along $x$, stay at the $xz$-plane ($y = 0$), and $2$ up.

Recap. The coordinate $y = 0$ for $Q$ means the point lies in the $xz$-plane. Points with one coordinate equal to zero lie in one of the three coordinate planes.


2. Equations Describing Simple Regions

A single equation in three variables describes a surface (not a curve).

Example 2. What does the equation $y = 4$ describe in 3D? (Stewart 12.1, Example 2.)

In 3D, $y = 4$ is a vertical plane parallel to the $xz$-plane, containing all points $(x, 4, z)$ for any $x$ and $z$.

Boxed answer: A plane parallel to the $xz$-plane, at $y = 4$.

Recap. In 2D the equation $y = 4$ is a horizontal line. In 3D it becomes a plane -- the two-dimensional constraint releases the third coordinate completely, so all values of $x$ and $z$ are allowed.


Common misconception

confusing 2D and 3D interpretations of an equation. The equation $x^2 + y^2 = 4$ describes a circle in the $xy$-plane. In 3D it describes an infinite cylinder of radius $2$ centered on the $z$-axis, because $z$ is unrestricted. The dimension of the space matters for every equation you encounter.


Common Errors Summary

Error Correction
Confusing $x$-axis and $y$-axis orientation Use the right-hand rule; the positive $z$-axis points up if $x$ is to the right and $y$ is forward
Reading $z = c$ as the $z$-axis $z = c$ is a plane, not a line; the $z$-axis is the set of all points $(0, 0, z)$
Thinking a one-variable equation in 3D gives a line One equation gives a surface; you need two equations for a line in 3D

Common Misconceptions

Common misconception

an equation in three variables always describes a curve.

This is the iconic-graph error. In two dimensions, one equation such as $x^2 + y^2 = 4$ describes a curve (a circle). In three dimensions, one equation describes a surface, because the missing variable is unconstrained. The equation $x^2 + y^2 = 4$ in 3D is an infinite cylinder of radius 2 centered on the $z$-axis. A curve in 3D requires two simultaneous equations.


Leveled Practice

Problem 1. Describe the set of all points $(x, y, z)$ satisfying $x^2 + z^2 = 9$, $y = 2$.

Show answer

$y = 2$ restricts to the plane at height $y = 2$. In that plane, $x^2 + z^2 = 9$ is a circle of radius $3$. Together: a circle of radius $3$ in the plane $y = 2$.


Problem 2. Describe the set $\{(x,y,z) : x^2 + y^2 \leq 1,\; 0 \leq z \leq 2\}$.

Show answer

$x^2 + y^2 \leq 1$ is a disk of radius $1$ in the $xy$-plane. $0 \leq z \leq 2$ stacks that disk from height $0$ to $2$. Together: a solid cylinder of radius $1$ and height $2$ with its base in the $xy$-plane.


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