You already know the Power Rule: $\frac{d}{dx}(x^n) = nx^{n-1}$. But what about $(x^2 + 1)^{10}$? You cannot just write $10(x^2+1)^9$. That ignores what is inside the parentheses.
The Generalized Power Rule fixes this by combining the Power Rule with the Chain Rule. It's arguably the most frequently used differentiation formula after the basic rules.
$$\frac{d}{dx}[g(x)]^n = n[g(x)]^{n-1} \cdot g'(x)$$
Key insight: Bring down the exponent, reduce by one, then multiply by the derivative of what's inside.
| Property | Value |
|---|---|
| Concept | Chain Rule |
| Chapter | 2.5 |
| Difficulty | Intermediate |
| Time | ~15 minutes |
For any differentiable function $g(x)$ and any real number $n$:
$$\boxed{\frac{d}{dx}[g(x)]^n = n[g(x)]^{n-1} \cdot g'(x)}$$
This is just the Chain Rule where the outer function is $f(u) = u^n$:
| Component | Value | Derivative |
|---|---|---|
| Outer: $f(u)$ | $u^n$ | $nu^{n-1}$ |
| Inner: $g(x)$ | whatever's inside | $g'(x)$ |
Chain Rule: $\frac{d}{dx}[g(x)]^n = f'(g(x)) \cdot g'(x) = n[g(x)]^{n-1} \cdot g'(x)$
For any expression of the form $(\text{stuff})^n$:
Example: $\frac{d}{dx}(x^3 + 2x)^7$
Step 1: Bring down 7 → 7
Step 2: Reduce exponent → 7(x³ + 2x)⁶
Step 3: Multiply by inside' → 7(x³ + 2x)⁶ · (3x² + 2)
The formula works for all real exponents:
| Expression | Rewrite | Derivative |
|---|---|---|
| $\sqrt{g(x)}$ | $[g(x)]^{1/2}$ | $\frac{1}{2}[g(x)]^{-1/2} \cdot g'(x) = \frac{g'(x)}{2\sqrt{g(x)}}$ |
| $\sqrt[3]{g(x)}$ | $[g(x)]^{1/3}$ | $\frac{1}{3}[g(x)]^{-2/3} \cdot g'(x)$ |
| $\frac{1}{g(x)}$ | $[g(x)]^{-1}$ | $-[g(x)]^{-2} \cdot g'(x) = \frac{-g'(x)}{[g(x)]^2}$ |
| $\frac{1}{[g(x)]^2}$ | $[g(x)]^{-2}$ | $-2[g(x)]^{-3} \cdot g'(x)$ |
Wrong: $\frac{d}{dx}(x^2 + 1)^5 = 5(x^2+1)^4$ ✗
This forgets the Chain Rule! The derivative of $x^2 + 1$ is $2x$, not 1.
Correct: $\frac{d}{dx}(x^2 + 1)^5 = 5(x^2+1)^4 \cdot 2x = 10x(x^2+1)^4$ ✓
Rule of thumb: If there's anything other than just "$x$" inside the parentheses, you need to multiply by its derivative.
Find $\frac{d}{dx}(4x - 7)^3$.
Find $f'(x)$ if $f(x) = (x^2 - 3x + 1)^8$.
Find $\frac{dy}{dx}$ if $y = \sqrt{5x^2 + 3}$.
Find $g'(t)$ if $g(t) = \frac{1}{(2t^3 - t)^4}$.
Find the derivative of $h(x) = (x+1)^3(x-2)^4$.
A student claims that $\frac{d}{dx}(x^2 + 5)^3 = 3(x^2 + 5)^2$.
Is this correct? If not, what is the correct answer and what step did the student miss?
The Gift-Wrapping Analogy: Think of $[g(x)]^n$ as a gift inside $n$ layers of wrapping paper.
If you forget step 2, you're only describing the wrapping paper, not what's actually changing inside!
Looking back:
Looking ahead:
Why this pattern is everywhere: Powers appear constantly in applications: areas ($r^2$), volumes ($r^3$), inverse-square laws ($1/r^2$), and growth models. Every time the base is a function, you need this rule.
| Previous | Up | Next |
|---|---|---|
| Chain Rule Formula | Skills Index | Implicit Differentiation |
Last updated: 2026-01-22