When we approximate areas under curves, we need to add up many terms—sometimes hundreds or thousands. Writing
$$f(x_1)\Delta x + f(x_2)\Delta x + f(x_3)\Delta x + \cdots + f(x_n)\Delta x$$
is tedious and imprecise (what exactly do the dots mean?). Sigma notation gives us a compact, precise way to write such sums.
The symbol $\Sigma$ (Greek capital "sigma") means "sum." It's like a compact for-loop in programming: it tells you what to add, where to start, and where to stop.
| Property | Value |
|---|---|
| Section | Stewart §4.1 |
| Course | MATH161 |
| Difficulty | Beginner |
| Time | ~15 minutes |
$$\sum_{i=1}^{n} a_i = a_1 + a_2 + a_3 + \cdots + a_n$$
Reading it: "The sum from $i = 1$ to $n$ of $a_i$"
Components:
n ← upper limit (stop here)
___
\
> a_i ← general term
/___
i=1 ← index and lower limit (start here)
To expand, substitute each integer from the lower limit to the upper limit:
$$\sum_{i=1}^{4} i^2 = 1^2 + 2^2 + 3^2 + 4^2 = 1 + 4 + 9 + 16 = 30$$
$$\sum_{j=0}^{3} 2^j = 2^0 + 2^1 + 2^2 + 2^3 = 1 + 2 + 4 + 8 = 15$$
To convert an explicit sum to sigma notation:
Example: Write $2 + 4 + 6 + 8 + 10$ in sigma notation.
These formulas let us evaluate sums without expanding:
$$\boxed{\sum_{i=1}^{n} c = nc} \quad \text{(sum of constant)}$$
$$\boxed{\sum_{i=1}^{n} i = \frac{n(n+1)}{2}} \quad \text{(sum of first } n \text{ integers)}$$
$$\boxed{\sum_{i=1}^{n} i^2 = \frac{n(n+1)(2n+1)}{6}} \quad \text{(sum of squares)}$$
$$\boxed{\sum_{i=1}^{n} i^3 = \left[\frac{n(n+1)}{2}\right]^2} \quad \text{(sum of cubes)}$$
$$\sum_{i=1}^{n} (a_i + b_i) = \sum_{i=1}^{n} a_i + \sum_{i=1}^{n} b_i$$
$$\sum_{i=1}^{n} c \cdot a_i = c \cdot \sum_{i=1}^{n} a_i$$
These let you break apart complicated sums!
The sum of rectangle areas can be written compactly:
$$R_n = f(x_1)\Delta x + f(x_2)\Delta x + \cdots + f(x_n)\Delta x = \sum_{i=1}^{n} f(x_i)\Delta x$$
This is why sigma notation is essential for integration.
Expand and evaluate:
(a) $\sum_{k=1}^{5} k$
(b) $\sum_{i=2}^{4} i^2$
(c) $\sum_{j=0}^{3} (2j + 1)$
Write each sum in sigma notation:
(a) $1 + 4 + 9 + 16 + 25$
(b) $\frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \frac{1}{16}$
(c) $3 + 6 + 9 + 12 + \cdots + 30$
Evaluate without expanding:
(a) $\sum_{i=1}^{100} i$
(b) $\sum_{k=1}^{20} k^2$
(c) $\sum_{j=1}^{50} (2j - 1)$
For $f(x) = x^2$ on $[0, 2]$ with $n$ subintervals of equal width:
(a) What is $\Delta x$?
(b) What is $x_i$ (the right endpoint of the $i$th subinterval)?
(c) Write $R_n$ (the right Riemann sum) in sigma notation.
(d) Use a summation formula to express $R_n$ as a single fraction in terms of $n$.
Using the result from Level 4, find:
$$\lim_{n \to \infty} R_n = \lim_{n \to \infty} \frac{4(n+1)(2n+1)}{3n^2}$$
What does this represent geometrically?
True or False (justify your answer):
(a) $\sum_{i=1}^{n} i$ and $\sum_{k=1}^{n} k$ represent the same sum.
(b) $\sum_{i=1}^{5} 3 = 3$
(c) $\sum_{i=1}^{n} (a_i \cdot b_i) = \left(\sum_{i=1}^{n} a_i\right) \cdot \left(\sum_{i=1}^{n} b_i\right)$
The For-Loop Analogy:
Think of sigma notation like a programming for-loop:
sum = 0
for i = 1 to n:
sum = sum + f(i)
This is exactly $\sum_{i=1}^{n} f(i)$. The index $i$ is just a counter that keeps track of which term we're on.
Looking back:
Looking ahead:
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|---|---|---|
| Closed Interval Method | Section Index | Riemann Sums |
Last updated: 2026-01-22