Navigation: Wiki Home > Skills > Computing Indefinite Integrals
Now that you understand the notation, it's time to build fluency. Computing indefinite integrals means recognizing patterns and applying formulas from your "table of integrals."
The good news: you already know these formulas—they're just your derivative formulas read backwards!
The key skill: combining basic formulas using linearity (sum rule and constant multiple rule) to handle more complex integrands.
graph LR
subgraph "Prerequisites"
A["Indefinite Integral<br/>Notation"]
B["Power Rule<br/>Antiderivatives"]
C["Trig<br/>Antiderivatives"]
end
subgraph "This Skill"
D["Computing<br/>Indefinite Integrals"]
end
subgraph "Unlocks"
E["Net Change<br/>Theorem"]
F["u-Substitution"]
G["Evaluating<br/>Definite Integrals"]
end
A --> D
B --> D
C --> D
D --> E
D --> F
D --> G
click A "indefinite-integral-notation.html"
click D "computing-indefinite-integrals.html"
click E "net-change-theorem.html"
click B "../ch2-sec3/power-rule.html"
click F "../ch4-sec5/u-substitution-definite.html"
click G "../ch4-sec2/definite-integral-evaluation.html"
From Indefinite Integral Notation:
From Power Rule Antiderivatives:
From Trig Antiderivatives:
If these feel unfamiliar, review the prerequisite pages before continuing.
| Property | Value |
|---|---|
| Concept | Indefinite Integrals & Net Change |
| Chapter | Chapter 4, Section 4 |
| Difficulty | Intermediate |
| Time | ~20 minutes |
$$\int x^n\, dx = \frac{x^{n+1}}{n+1} + C \quad (n \neq -1)$$
$$\int k\, dx = kx + C \quad \text{(constant)}$$
| Integral | Result |
|---|---|
| $\int \sin x\, dx$ | $-\cos x + C$ |
| $\int \cos x\, dx$ | $\sin x + C$ |
| $\int \sec^2 x\, dx$ | $\tan x + C$ |
| $\int \csc^2 x\, dx$ | $-\cot x + C$ |
| $\int \sec x \tan x\, dx$ | $\sec x + C$ |
| $\int \csc x \cot x\, dx$ | $-\csc x + C$ |
These let you break complex integrals into simpler pieces:
Constant Multiple Rule: $$\int c \cdot f(x)\, dx = c \int f(x)\, dx$$
Sum/Difference Rule: $$\int [f(x) \pm g(x)]\, dx = \int f(x)\, dx \pm \int g(x)\, dx$$
Strategy: Always simplify the integrand FIRST, then apply linearity to separate terms, then integrate term by term.
Many integrands look complicated but become easy after algebraic simplification:
Example: $\int \frac{x^3 + 2x}{x}\, dx$
Don't try to integrate this directly! Simplify first: $$= \int \left(x^2 + 2\right)\, dx = \frac{x^3}{3} + 2x + C$$
| Pattern | Strategy |
|---|---|
| $\frac{a + b}{c}$ | Split into $\frac{a}{c} + \frac{b}{c}$ |
| $x^a \cdot x^b$ | Combine to $x^{a+b}$ |
| $\sqrt{x} = x^{1/2}$ | Rewrite as power |
| $\frac{1}{x^n} = x^{-n}$ | Rewrite as power |
| $\sqrt[n]{x^m} = x^{m/n}$ | Rewrite as power |
Find the general indefinite integral:
$$\int (3x^2 + 4x + 1)\, dx$$
Find the general indefinite integral:
$$\int (4\sec^2 x - 2\sin x)\, dx$$
Find the general indefinite integral:
$$\int \frac{2t^3 + t^2\sqrt{t}}{t^2}\, dt$$
Find the general indefinite integral:
$$\int \frac{\cos\theta}{\sin^2\theta}\, d\theta$$
Hint: Rewrite using trig identities.
The power rule states $\int x^n\, dx = \frac{x^{n+1}}{n+1} + C$ for $n \neq -1$.
(a) What happens algebraically if you try to apply this formula when $n = -1$?
(b) We know $\frac{d}{dx}[\ln\vert x\vert ] = \frac{1}{x}$. Use this to explain what $\int x^{-1}\, dx$ actually equals.
(c) Deeper question: The function $f(x) = \frac{x^{n+1}}{n+1}$ is continuous for all $n > -1$ and all $n < -1$. What happens to this function as $n \to -1$? Does it "approach" $\ln\vert x\vert $ in any sense?
Integration as "Reverse Engineering"
Imagine each integral formula as a puzzle piece. The question is: "What function, when differentiated, gives me this?"
Your table of integrals is your collection of solved puzzles. For complex problems:
| Error | Correction |
|---|---|
| $\int 3x^2\, dx = 3x^3 + C$ | Should be $x^3 + C$ (the 3 divides out) |
| $\int x^{-1}\, dx = \frac{x^0}{0}$ | Power rule doesn't work for $n = -1$! Use $\ln\vert x\vert + C$ |
| Multiple $+C$'s | Only ONE $+C$ per integral |
| Forgetting to simplify | $\int \frac{x^2 + 1}{x}\, dx \neq$ hard! Simplify first. |
Looking back:
Looking ahead:
Real-world connections:
| Previous | Up | Next |
|---|---|---|
| Indefinite Integral Notation | Skills Index | Net Change Theorem |
Last updated: 2026-01-22