How do you find the volume of an irregularly shaped solid? You can't just measure length times width times height when the shape keeps changing. But here's an idea: slice it.
Think of a loaf of bread. Each slice has a certain area, and if you add up the volumes of all the thin slices (area × thickness), you get the total volume. The thinner the slices, the more accurate your answer. In the limit of infinitely thin slices, you get the exact volume, and that limit is a definite integral.
The key insight: Volume is to area what area was to length. Just as we built up area by integrating lengths, we build up volume by integrating areas.
Self-check: Can you answer these questions? If not, review the linked prerequisites first.
| Question | If you struggle... |
|---|---|
| Evaluate $\int_0^3 x^2\,dx$ | Review Definite Integrals |
| Explain why $\lim_{n\to\infty}\sum_{i=1}^n f(x_i^*)\Delta x = \int_a^b f(x)\,dx$ | Review Riemann Sums |
| Find the area of a circle with radius 5 | Review geometric area formulas |
The definite integral is defined as: $$\int_a^b f(x)\,dx = \lim_{n\to\infty}\sum_{i=1}^n f(x_i^*)\Delta x$$
where $\Delta x = \frac{b-a}{n}$ and $x_i^*$ is a sample point in the $i$-th subinterval.
Key idea: We approximate the quantity (area, in the basic case) with a sum of simple pieces, then take the limit as the pieces become infinitely small.
| Shape | Area Formula |
|---|---|
| Rectangle | $A = \ell \times w$ |
| Circle | $A = \pi r^2$ |
| Triangle | $A = \frac{1}{2}bh$ |
| Trapezoid | $A = \frac{1}{2}(b_1 + b_2)h$ |
These formulas are essential for computing cross-sectional areas.
| Property | Value |
|---|---|
| Concept | Applications of Integration |
| Course | MATH162 |
| Section | Stewart 5.2 |
| Difficulty | Intermediate |
| Time | ~25 minutes |
Consider a solid $S$ lying between $x = a$ and $x = b$. At each point $x$, slice the solid with a plane perpendicular to the $x$-axis. This produces a cross-section with area $A(x)$.
y
| _____
| / \ ← Solid S
| / | \
| / A(x) \ ← Cross-section at x has area A(x)
| / | \
+-------|------→ x
x
a b
$$\boxed{V = \int_a^b A(x)\,dx}$$
where:
Divide the solid into $n$ thin slabs of equal width $\Delta x = \frac{b-a}{n}$.
Step 1: Approximate each slab as a cylinder with base area $A(x_i^*)$ and height $\Delta x$.
Step 2: The volume of the $i$-th slab is approximately $A(x_i^*)\Delta x$.
Step 3: Sum all slabs: $$V \approx \sum_{i=1}^n A(x_i^*)\Delta x$$
Step 4: Take the limit as $n \to \infty$: $$V = \lim_{n \to \infty} \sum_{i=1}^n A(x_i^*)\Delta x = \int_a^b A(x)\,dx$$
The approximation becomes exact because the integral captures the continuous variation in cross-sectional area.
For a cylinder (where the cross-section doesn't change), $A(x) = A$ for all $x$:
$$V = \int_a^b A\,dx = A(b - a) = A \cdot h$$
This confirms the familiar formula: Volume = Base Area × Height.
You can slice perpendicular to any axis. If cross-sections are perpendicular to the $y$-axis:
$$V = \int_c^d A(y)\,dy$$
How do you choose? Pick the axis that makes $A$ easiest to express. If the solid's shape varies more naturally along one direction, that's usually your integration variable.
| Mistake | Why It's Wrong | Correction |
|---|---|---|
| Wrong axis of integration | Cross-sections must be perpendicular to the axis of integration | If slices are perpendicular to $x$-axis, integrate with respect to $x$ |
| Forgetting continuity requirement | The formula assumes $A(x)$ is continuous on $[a,b]$ | Check for discontinuities; split the integral if needed |
| Wrong limits | Limits must be where the solid begins and ends, not the function | Identify the extent of the solid along the axis |
| Confusing $A(x)$ with $f(x)$ | $A(x)$ is the cross-sectional area, not the function defining the boundary | Area often involves squaring: $A = \pi r^2$, $A = s^2$, etc. |
A cylinder has circular cross-sections of radius 3 and extends from $x = 0$ to $x = 5$. Use the slicing formula to find its volume.
Find the volume of a hemisphere of radius 5 by integrating circular cross-sections. (The hemisphere is the upper half of a sphere.)
Find the volume of a pyramid with height 6 and a rectangular base measuring 4 by 8. Place the apex at the origin with the axis along the positive $z$-axis.
A wedge is cut from a circular cylinder of radius 3 by two planes. One plane is perpendicular to the axis of the cylinder. The other intersects the first at an angle of $45°$ along a diameter of the cylinder. Find the volume of the wedge.
Cavalieri's Principle: If two solids have equal cross-sectional areas at every height, they have equal volumes.
The Bread Slicer: Imagine an infinitely sharp bread slicer that can cut arbitrarily thin slices. Each slice is a flat disk of area $A(x)$ and thickness $dx$. The volume of each infinitesimal slice is $A(x)\,dx$, and the total volume is the "sum" (integral) of all these slices from one end of the loaf to the other.
Looking back:
Looking ahead:
| Previous | Up | Next |
|---|---|---|
| Properties of Integrals | Skills Index | Disk Method |
Last updated: 2026-01-23