Derivatives of Sine and Cosine
Why These Two Derivatives Matter
Every oscillating system in nature (a swinging pendulum, a vibrating guitar string, an alternating current) is described by sine and cosine functions. To understand how fast these systems change at any moment, we need their derivatives.
Here’s the beautiful surprise: the derivative of sine is cosine, and the derivative of cosine is negative sine. These two functions are intertwined in a cycle that repeats every four derivatives. This elegant pattern makes trigonometric derivatives some of the most memorable in all of calculus.
Prerequisite Map
Quick Reference
| Property | Value |
|---|---|
| Concept | Trigonometric Derivatives |
| Chapter | 2.4 |
| Difficulty | Intermediate |
| Time | ~20 minutes |
Key Formulas
$$\boxed{\frac{d}{dx}(\sin x) = \cos x}$$
$$\boxed{\frac{d}{dx}(\cos x) = -\sin x}$$
Critical reminder: These formulas are only valid when $x$ is measured in radians. If you work in degrees, you’ll get an extra factor of $\pi/180$.
The Two Essential Limits
Before we can prove these formulas, we need two special limits:
$$\lim_{\theta \to 0} \frac{\sin \theta}{\theta} = 1 \qquad \lim_{\theta \to 0} \frac{\cos \theta - 1}{\theta} = 0$$
Why $\frac{\sin \theta}{\theta} \to 1$?
For small angles (in radians), the sine of the angle is approximately equal to the angle itself:
Arc length = θ (on unit circle)
↗
/
/|
/ | Height = sin θ
/ |
/θ__|
O
For small θ: sin θ ≈ θ
The Squeeze Theorem makes this rigorous: $\cos \theta < \frac{\sin \theta}{\theta} < 1$ for small positive $\theta$, and both bounds approach 1.
Proof: Derivative of Sine
Starting from the definition:
$$\frac{d}{dx}(\sin x) = \lim_{h \to 0} \frac{\sin(x+h) - \sin x}{h}$$
Using the angle addition formula $\sin(x+h) = \sin x \cos h + \cos x \sin h$:
$$= \lim_{h \to 0} \frac{\sin x \cos h + \cos x \sin h - \sin x}{h}$$
$$= \lim_{h \to 0} \left( \sin x \cdot \frac{\cos h - 1}{h} + \cos x \cdot \frac{\sin h}{h} \right)$$
$$= \sin x \cdot 0 + \cos x \cdot 1 = \cos x$$
The Cyclic Pattern
The derivatives of sine and cosine repeat in a cycle of four:
| $n$ | $\frac{d^n}{dx^n}(\sin x)$ | $\frac{d^n}{dx^n}(\cos x)$ |
|---|---|---|
| 0 | $\sin x$ | $\cos x$ |
| 1 | $\cos x$ | $-\sin x$ |
| 2 | $-\sin x$ | $-\cos x$ |
| 3 | $-\cos x$ | $\sin x$ |
| 4 | $\sin x$ | $\cos x$ |
Pattern: Differentiating four times returns you to the original function.
Finding the $n$th derivative: Divide $n$ by 4 and look at the remainder.
- Remainder 0: back to original
- Remainder 1: first derivative
- Remainder 2: second derivative
- Remainder 3: third derivative
Physical Interpretation
For simple harmonic motion with position $s(t) = A\sin(t)$:
- Position: $s = A\sin t$
- Velocity: $v = \frac{ds}{dt} = A\cos t$
- Acceleration: $a = \frac{dv}{dt} = -A\sin t$
Notice: $a = -s$. The acceleration is proportional to position but opposite in sign. This is the defining property of simple harmonic motion.
Position: ∿∿∿∿∿ (sine wave)
↓ derivative
Velocity: ∿∿∿∿∿ (cosine = shifted sine)
↓ derivative
Acceleration: ∿∿∿∿∿ (negative sine)
When position is at maximum, velocity is zero. When position crosses zero, velocity is at maximum.
Practice Problems
Find $\frac{d}{dx}(5\sin x - 3\cos x)$.
Find $\frac{d}{dx}(x^3 \sin x)$.
Find the equation of the tangent line to $y = \sin x + \cos x$ at the point where $x = 0$.
Find $\frac{d^{83}}{dx^{83}}(\cos x)$.
Prove that $\frac{d}{dx}(\cos x) = -\sin x$ using the definition of the derivative.
Hint: Use the angle addition formula $\cos(x+h) = \cos x \cos h - \sin x \sin h$ and the two special limits.
CCI-Style Conceptual Questions
The graph below shows $f(x) = \sin x$.
1 | ∩
| / \
0 |--/-----\-----/--
| \ /
-1 | ∪
0 π/2 π 3π/2 2π
At which point(s) is $f'(x) = 0$?
- At $x = 0$ and $x = \pi$
- At $x = \pi/2$ and $x = 3\pi/2$
- At $x = \pi$ only
- At $x = 0, \pi/2, \pi, 3\pi/2$
If $f(x) = \cos x$, then on the interval $(0, \pi)$:
- $f'(x) > 0$ for all $x$ in $(0, \pi)$
- $f'(x) < 0$ for all $x$ in $(0, \pi)$
- $f'(x) > 0$ for $x$ in $(0, \pi/2)$ and $f'(x) < 0$ for $x$ in $(\pi/2, \pi)$
- $f'(x) = 0$ for all $x$ in $(0, \pi)$
Common Misconceptions
the derivative formulas $(\sin x)' = \cos x$ and $(\cos x)' = -\sin x$ work regardless of the angle unit used.
This is the radian-as-arc-length-in-radius-units error. Radians are defined as a dimensionless ratio (arc length divided by radius), and the limit $\lim_{\theta \to 0} \frac{\sin \theta}{\theta} = 1$ holds only when $\theta$ is measured in radians. When $x$ is in degrees, the same limit evaluates to $\pi/180$, and the chain rule introduces that factor: $\frac{d}{dx}[\sin(x^\circ)] = \frac{\pi}{180}\cos(x^\circ)$. Using $(\sin x)' = \cos x$ in degree measure gives an answer off by a factor of approximately $0.01745$.
$\sin$ and $\cos$ are symbols that can be separated from their argument like multipliers.
This is the trig-as-algebra-symbols error. Students sometimes write $\sin(x + h) = \sin x + \sin h$, treating $\sin$ as a factor that distributes over addition. The correct expansion requires the angle addition formula: $\sin(x + h) = \sin x \cos h + \cos x \sin h$. The distinction matters in the proof of $(\sin x)' = \cos x$: the derivation uses the addition formula at the key step, and treating sine as distributive makes the proof collapse entirely.
Mastery Checklist
Mental Model
The Phase Shift Connection:
Think of $\cos x$ as a sine wave shifted left by $\pi/2$:
$$\cos x = \sin\left(x + \frac{\pi}{2}\right)$$
When you differentiate sine, you get cosine, a function that is $\pi/2$ ahead in the wave cycle. Differentiating again shifts another $\pi/2$, giving $-\sin x$ (which is $\pi$ ahead, i.e., the negative).
Four shifts of $\pi/2$ brings you full circle: $4 \times \frac{\pi}{2} = 2\pi$, which is one complete period.
Connections
Looking back:
- The derivative definition is the foundation for proving these formulas
- Limit laws let us split the proof into manageable pieces
Looking ahead:
- Other trig derivatives builds on these using the quotient rule
- The chain rule lets us differentiate $\sin(3x)$, $\cos(x^2)$, etc.
Real-world connections:
- In physics, these derivatives describe velocity and acceleration of oscillating systems
- In electrical engineering, they model alternating current circuits
| Previous | Up | Next |
|---|---|---|
| Basic Differentiation Rules | Skills Index | Derivatives of Other Trig Functions |
Last updated: 2026-01-22