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Evaluating Definite Integrals

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Reference: Stewart §4.2

Textbook Reference

Primary source OpenStax Calculus Volume 2, Section 1.2: “The Definite Integral”
Direct link https://openstax.org/books/calculus-volume-2/pages/1-2-the-definite-integral
Textbook used in class Stewart, Calculus, Section 4.2: “The Definite Integral”

Opening Scenario

The area problem and the distance problem both lead to the same limit: a sum of many small products $f(x_i^*)\,\Delta x$ as $\Delta x \to 0$. This limit is so important that it gets its own name and notation: the definite integral.

But area and distance are always positive. What happens when $f$ dips below the $x$-axis? The definite integral is still defined there -- it just measures signed area, where regions below the $x$-axis contribute negatively.


Quick Reference

Definition. If $f$ is integrable on $[a, b]$, then $$\int_a^b f(x)\,dx = \lim_{n\to\infty} \sum_{i=1}^{n} f(x_i^*)\,\Delta x$$ where $\Delta x = \dfrac{b-a}{n}$ and $x_i^*$ is any point in the $i$-th subinterval.

Reading: “The integral from $a$ to $b$ of $f(x)$ with respect to $x$.”

Parts of the notation:

Geometric interpretation: $\displaystyle\int_a^b f(x)\,dx$ = (area above $x$-axis) $-$ (area below $x$-axis).


Key Concepts

1. The Definite Integral Is a Number

Unlike the derivative, which is a new function, the definite integral of $f$ on $[a, b]$ is a single real number. Once $a$, $b$, and $f$ are specified, $\int_a^b f(x)\,dx$ is determined. The variable $x$ inside is a dummy variable: $\int_a^b f(x)\,dx$, $\int_a^b f(t)\,dt$, and $\int_a^b f(u)\,du$ all denote the same number.

2. Signed Area

When $f(x) \geq 0$ on $[a, b]$, the definite integral equals the area of the region below $y = f(x)$ and above the $x$-axis -- precisely the area problem from Section 4.1.

When $f(x) < 0$ on part of $[a, b]$, the rectangles in that part have negative height $f(x_i^*)$, so they contribute negatively to the sum. The integral counts area above the $x$-axis as positive and area below the $x$-axis as negative.

Example. If $f(x) = \sin x$ on $[0, 2\pi]$, the first arch (above the axis on $[0, \pi]$) and the second arch (below the axis on $[\pi, 2\pi]$) have equal areas. They cancel, so $\displaystyle\int_0^{2\pi} \sin x\,dx = 0$.

3. Evaluating by Geometry

For simple functions, the definite integral can be read off from the geometry of the graph.

Geometric evaluation works only for simple shapes. For general functions, the Fundamental Theorem of Calculus (Section 4.3) provides the practical tool.

4. Evaluating by Definition

For polynomial functions, the summation formulas from Section 4.1 allow computation of the exact integral directly from the Riemann sum limit.

Common misconception

“$\int_a^b f(x)\,dx$ always gives area.” The definite integral gives signed area. To find the total (unsigned) area between $f$ and the $x$-axis, split the integral at the zeros of $f$ and add the absolute values of each piece.


Worked Example

Evaluate $\displaystyle\int_0^2 (x - 1)\,dx$ using geometry.

The line $y = x - 1$ crosses the $x$-axis at $x = 1$.

On $[0, 1]$: triangle below the $x$-axis, base 1, height 1. Signed contribution: $-\dfrac{1}{2}$.

On $[1, 2]$: triangle above the $x$-axis, base 1, height 1. Signed contribution: $+\dfrac{1}{2}$.

$$\int_0^2 (x-1)\,dx = -\frac{1}{2} + \frac{1}{2} = 0.$$

Boxed answer: $\displaystyle\int_0^2 (x-1)\,dx = 0$.


Evaluate $\displaystyle\int_0^3 x^2\,dx$ using the definition.

$\Delta x = \dfrac{3}{n}$, $x_i = \dfrac{3i}{n}$.

$$\int_0^3 x^2\,dx = \lim_{n\to\infty}\frac{27}{n^3}\cdot\frac{n(n+1)(2n+1)}{6} = \lim_{n\to\infty}\frac{27(n+1)(2n+1)}{6n^2} = \frac{27 \cdot 2}{6} = 9.$$

Boxed answer: $\displaystyle\int_0^3 x^2\,dx = 9$.


Common Errors Summary

Error Example Correction
Treating the integral as always positive Writing $\int_0^{2\pi}\sin x\,dx = 2$ Signed areas cancel; the integral is 0
Confusing dummy variable with a real variable Thinking $\int_a^b f(x)\,dx \neq \int_a^b f(t)\,dt$ Both denote the same number; the integration variable is internal
Reporting a Riemann sum as the exact value Writing $R_{10} = $ exact area The exact value requires $\lim_{n\to\infty}$, not any finite $n$

Leveled Practice

Level 1 -- Geometric Evaluation

Problem 1. Evaluate $\displaystyle\int_1^4 3\,dx$ using the geometry of the graph.

Show answer

Rectangle: width $4 - 1 = 3$, height $3$.

$\displaystyle\int_1^4 3\,dx = 9$.


Level 2 -- Signed Area

Problem 2. Evaluate $\displaystyle\int_0^4 (2x - 4)\,dx$ using geometry.

Show answer

Zero at $x = 2$. Triangle below axis on $[0,2]$: base 2, height 4, area 4. Contribution $-4$. Triangle above axis on $[2,4]$: base 2, height 4, area 4. Contribution $+4$.

$\displaystyle\int_0^4(2x-4)\,dx = -4 + 4 = 0$.


Mastery Checklist


Mental Model

The integral sign $\int$ is a stretched-out $S$ for “sum.” The $dx$ is the limiting form of $\Delta x$. The integrand $f(x)$ is the height. So $\int_a^b f(x)\,dx$ literally means “sum of $f(x)\,\Delta x$ as widths shrink to zero,” written in compact form.

The word “definite” signals that the limits $a$ and $b$ are fixed, so the result is a specific number, not a family of functions.


Connections

Looking back

Looking ahead


Back to Integration Foundations | Next: Properties of the Definite Integral