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Properties of the Definite Integral

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Reference: Stewart §4.2

Textbook Reference

Primary source OpenStax Calculus Volume 2, Section 1.2: “The Definite Integral”
Direct link https://openstax.org/books/calculus-volume-2/pages/1-2-the-definite-integral
Textbook used in class Stewart, Calculus, Section 4.2: “The Definite Integral”

Opening Scenario

Computing $\displaystyle\int_0^5 (3x^2 - 2x + 7)\,dx$ from the limit definition would require three separate summation formulas and careful algebra. Instead, a small set of properties -- inherited directly from the Riemann sum definition -- lets you split, scale, and combine integrals. These properties are not shortcuts; they are exact equalities that follow from the definition.


Quick Reference

Let $f$ and $g$ be integrable on $[a, b]$ and let $c$ be a constant.

Convention: $\displaystyle\int_a^a f(x)\,dx = 0$. $\quad$ $\displaystyle\int_b^a f(x)\,dx = -\int_a^b f(x)\,dx$.

Constant multiple: $\displaystyle\int_a^b c\,f(x)\,dx = c\int_a^b f(x)\,dx$.

Sum/difference: $\displaystyle\int_a^b [f(x) \pm g(x)]\,dx = \int_a^b f(x)\,dx \pm \int_a^b g(x)\,dx$.

Additivity over intervals: $\displaystyle\int_a^b f(x)\,dx + \int_b^c f(x)\,dx = \int_a^c f(x)\,dx$.

Comparison: If $f(x) \geq g(x)$ on $[a, b]$, then $\displaystyle\int_a^b f(x)\,dx \geq \int_a^b g(x)\,dx$.

Bound: If $m \leq f(x) \leq M$ on $[a, b]$, then $m(b-a) \leq \displaystyle\int_a^b f(x)\,dx \leq M(b-a)$.


Key Concepts

1. Linearity

The sum and constant-multiple rules together say that integration is linear: $$\int_a^b [c_1 f(x) + c_2 g(x)]\,dx = c_1 \int_a^b f(x)\,dx + c_2 \int_a^b g(x)\,dx.$$

This follows directly from the linearity of finite sums: $\sum (c_1 a_i + c_2 b_i) = c_1 \sum a_i + c_2 \sum b_i$. Since each Riemann sum has this property, so does the limit.

Practical use. Break a complicated integrand into simpler pieces, integrate each piece, and combine.

2. Interval Additivity

$\displaystyle\int_a^c f(x)\,dx = \int_a^b f(x)\,dx + \int_b^c f(x)\,dx$ for any $b$ between $a$ and $c$ (or even outside $[a, c]$ if the integrals exist).

Geometrically: the total signed area from $a$ to $c$ equals the signed area from $a$ to $b$ plus the signed area from $b$ to $c$. The point $b$ can be anywhere -- it just splits the region.

Practical use. If $f$ changes sign at $x = b$, compute $\int_a^b$ and $\int_b^c$ separately, then add. This is necessary to find total (unsigned) area.

3. Reversed Limits

$$\int_b^a f(x)\,dx = -\int_a^b f(x)\,dx.$$

The definition assigns a sign based on orientation. Swapping the limits negates the integral. This convention ensures that the additivity property holds even when $b$ is not between $a$ and $c$.

4. Comparison and Bounding

If $f(x) \geq 0$ on $[a, b]$, then $\displaystyle\int_a^b f(x)\,dx \geq 0$. More generally, if $m \leq f(x) \leq M$ on $[a, b]$, then the integral is trapped between $m(b-a)$ and $M(b-a)$.

This bounding property is useful for estimating integrals when an exact antiderivative is difficult to find.

Common misconception

“You can factor a function of $x$ out of an integral.” The constant-multiple rule allows $\int_a^b c\,f(x)\,dx = c\int_a^b f(x)\,dx$ when $c$ does not depend on $x$. You cannot write $\int_a^b x\cdot f(x)\,dx = x\int_a^b f(x)\,dx$ because $x$ is the variable of integration, not a constant.


Worked Example

Given $\displaystyle\int_0^5 f(x)\,dx = 8$ and $\displaystyle\int_0^5 g(x)\,dx = 3$, evaluate:

(a) $\displaystyle\int_0^5 [2f(x) - 4g(x)]\,dx$

By linearity: $2(8) - 4(3) = 16 - 12 = 4$.

(b) $\displaystyle\int_5^0 f(x)\,dx$

By the reversed-limits rule: $-\displaystyle\int_0^5 f(x)\,dx = -8$.

Boxed answers: (a) $4$; (b) $-8$.


Given $\displaystyle\int_1^3 f(x)\,dx = 5$ and $\displaystyle\int_3^7 f(x)\,dx = -2$, find $\displaystyle\int_1^7 f(x)\,dx$.

By additivity: $5 + (-2) = 3$.

Boxed answer: $\displaystyle\int_1^7 f(x)\,dx = 3$.


Common Errors Summary

Error Example Correction
Factoring a variable out of an integral $\int_0^1 x e^x\,dx = x\int_0^1 e^x\,dx$ $x$ is the integration variable; only constants can be factored out
Thinking $\int_a^b f \cdot g = \int_a^b f \cdot \int_a^b g$ Splitting a product into a product of integrals Integrals do not distribute over products (integration by parts handles products instead)
Forgetting the sign reversal when limits swap Writing $\int_3^1 f\,dx = \int_1^3 f\,dx$ $\int_3^1 f\,dx = -\int_1^3 f\,dx$

Leveled Practice

Level 1 -- Direct Application

Problem 1. If $\displaystyle\int_0^3 f(x)\,dx = 10$, find $\displaystyle\int_0^3 5f(x)\,dx$.

Show answer

$5 \times 10 = 50$.


Level 2 -- Combining Properties

Problem 2. Given $\displaystyle\int_0^2 f = 4$, $\displaystyle\int_2^5 f = -1$, and $\displaystyle\int_0^5 g = 6$, evaluate $\displaystyle\int_0^5 [f(x) + 2g(x)]\,dx$.

Show answer

$\int_0^5 f = 4 + (-1) = 3$ (additivity). $\int_0^5 2g = 2(6) = 12$.

$\displaystyle\int_0^5 [f + 2g]\,dx = 3 + 12 = 15$.


Level 3 -- Bounding

Problem 3. Use the bound property to estimate $\displaystyle\int_0^{\pi/2} \sin x\,dx$ without computing it.

Show answer

On $[0, \pi/2]$, $\sin x$ ranges from $0$ to $1$. So $m = 0$, $M = 1$, $b - a = \pi/2$.

$0 \leq \displaystyle\int_0^{\pi/2} \sin x\,dx \leq \frac{\pi}{2} \approx 1.57$.

(The exact value is $1$, which is indeed between 0 and 1.57.)


Mastery Checklist


Mental Model

The properties of the definite integral mirror the properties of ordinary sums because the integral is a limit of sums. Scaling every term of a sum by $c$ scales the total by $c$. Adding two sequences and summing is the same as summing each sequence and adding the totals. Splitting a sum at an intermediate index and adding both parts recovers the original total. Each property of the integral is just its summation counterpart, taken to the limit.


Connections

Looking back

Looking ahead


Back to Integration Foundations | Next: Applying the FTC