Quick Decision Guide
Axis Direction Shells Use Washers Use Vertical ($y$-axis, $x = k$) Vertical strips, $dx$ Horizontal slices, $dy$ Horizontal ($x$-axis, $y = k$) Horizontal strips, $dy$ Vertical slices, $dx$ The Key Question: Which variable describes the region more naturally?
- If $y = f(x)$ is given and easy to use → favor $dx$ integrals
- If $x = g(y)$ is given or $f(x)$ is easy to invert → favor $dy$ integrals
For rotation about $x = k$: $$V = \int 2\pi \lvert x - k \rvert \cdot (\text{height}) \, dx$$
If unclear, review Shell Method: Other Axes.
$$V = \int \pi [R(x)^2 - r(x)^2] \, dx$$
where $R$ is the outer radius and $r$ is the inner radius.
If unclear, review Disk/Washer Method.
Answer: $x = \sqrt{y}$ (for $x \geq 0$) or $x = -\sqrt{y}$ (for $x \leq 0$).
Inverting functions is often the deciding factor in which method to choose.
You have a region. You need to rotate it about an axis. You have two methods: shells and washers. Which one should you use?
The answer depends on three factors:
This skill teaches you to make that choice quickly and confidently.
| Property | Value |
|---|---|
| Chapter | 5 - Applications of Integration |
| Section | 5.3 |
| Difficulty | Intermediate |
| Time | ~25 minutes |
| Aspect | Washers/Disks | Shells |
|---|---|---|
| Slice direction | Perpendicular to axis | Parallel to axis |
| Shape of slice | Circular cross-section | Cylindrical tube |
| Integration variable | Same direction as axis | Opposite direction to axis |
| Formula structure | $\pi R^2 - \pi r^2$ | $2\pi r h$ |
┌─────────────────────────────┐
│ What axis of rotation? │
└─────────────┬───────────────┘
│
┌─────────────────┴─────────────────┐
│ │
┌───────▼───────┐ ┌───────▼───────┐
│ Vertical axis │ │ Horizontal │
│ (y-axis, x=k) │ │ axis (x-axis, │
│ │ │ y=k) │
└───────┬───────┘ └───────┬───────┘
│ │
┌───────┴───────┐ ┌───────┴───────┐
│ │ │ │
▼ ▼ ▼ ▼
┌─────────┐ ┌─────────┐ ┌─────────┐ ┌─────────┐
│ Washers │ │ Shells │ │ Washers │ │ Shells │
│ use dy │ │ use dx │ │ use dx │ │ use dy │
└─────────┘ └─────────┘ └─────────┘ └─────────┘Rule 1: Match the natural description
| Region Description | Favored Variable | Reason |
|---|---|---|
| $y = f(x)$ given, $f$ is complicated | $dx$ | Avoid solving for $x$ |
| $x = g(y)$ given | $dy$ | Natural form |
| $y = f(x)$ is easy to invert | Either | Choose based on axis |
Rule 2: Match variable to method
| Axis Direction | To use $dx$ | To use $dy$ |
|---|---|---|
| Vertical ($x = k$) | Shells | Washers |
| Horizontal ($y = k$) | Washers | Shells |
Rule 3: Combine Rules 1 and 2
| Situation | Best Choice |
|---|---|
| Vertical axis + $y = f(x)$ natural | Shells (both favor $dx$) |
| Vertical axis + $x = g(y)$ natural | Washers (both favor $dy$) |
| Horizontal axis + $y = f(x)$ natural | Washers (both favor $dx$) |
| Horizontal axis + $x = g(y)$ natural | Shells (both favor $dy$) |
Use shells when:
| Situation | Example | Why Shells Win |
|---|---|---|
| $y = f(x)$ is hard to invert | $y = x^3 - x$ | Avoid cubic formula |
| Function has multiple branches | $y^2 = x$ gives $y = \pm\sqrt{x}$ | One integral vs. two |
| Rotating about vertical axis with $y = f(x)$ | Standard setup | Natural match |
Use washers when:
| Situation | Example | Why Washers Win |
|---|---|---|
| Region has obvious inner/outer radii | Annular region | Direct application |
| Rotating about $x$-axis with simple $f(x)$ | $y = x^2$ | Just square the function |
| $x = g(y)$ is the given form | $x = y^2$ | Natural match |
Visual test: Draw a thin strip in the region. Which direction is it?
Vertical axis Horizontal axis
│ ═══
┌─────┼─────┐ ┌─────────────┐
│ │ │ │ │ ← vertical │ ─ ─ ─ ─ ─ │ ← horizontal
│ │ │ │ │ strips │ ─ ─ ─ ─ ─ │ strips
│ │ │ │ │ = SHELLS │ ─ ─ ─ ─ ─ │ = SHELLS
└─────┴─────┘ └─────────────┘
┌───────────┐ ┌─────────────┐
│ ───────── │ ← horizontal │ │ │ │ │ │ ← vertical
│ ───────── │ strips │ │ │ │ │ │ strips
│ ───────── │ = WASHERS │ │ │ │ │ │ = WASHERS
└───────────┘ └─────────────┘Shells (use $dx$): $$V = \int_0^2 2\pi x \cdot x^3 \, dx = 2\pi \int_0^2 x^4 \, dx = 2\pi \cdot \frac{32}{5} = \frac{64\pi}{5}$$
Washers (use $dy$, need $x = y^{1/3}$):
Bounds: $y \in [0, 8]$ $$V = \int_0^8 \pi(4 - y^{2/3}) \, dy = \pi\left[4y - \frac{3y^{5/3}}{5}\right]_0^8 = \pi\left(32 - \frac{96}{5}\right) = \frac{64\pi}{5}$$
Verdict: Both work. Shells required slightly fewer steps (no cube root inversion needed).
Shells (use $dx$): $$V = \int_0^4 2\pi x(4x^2 - x^3) \, dx = 2\pi \int_0^4 (4x^3 - x^4) \, dx$$
Straightforward polynomial integration gives $V = \frac{512\pi}{5}$.
Washers (use $dy$):
Would need to solve $y = 4x^2 - x^3$ for $x$ in terms of $y$. This cubic equation has no nice closed form—you'd need the cubic formula.
Verdict: Shells win decisively. This type of problem is exactly why the shell method was developed.
Washers (use $dx$): $$V = \int_0^8 \pi(x^{1/3})^2 \, dx = \pi \int_0^8 x^{2/3} \, dx = \pi \cdot \frac{3(32)}{5} = \frac{96\pi}{5}$$
Shells (use $dy$, need $x = y^3$): $$V = \int_0^2 2\pi y(8 - y^3) \, dy = 2\pi \int_0^2 (8y - y^4) \, dy = \frac{96\pi}{5}$$
Verdict: Both work. Washers slightly simpler (just square the function).
This isn't coincidence—it's a theorem. Both methods compute the same volume by summing up pieces differently:
It's like computing the area of a rectangle as (width × height) vs. (height × width)—different approaches, same answer.
The fact that both methods agree provides a powerful verification technique: if you're unsure of your answer, try the other method!
For each situation, state whether shells or washers would be simpler (don't solve):
The region bounded by $y = \sqrt{x}$ and $y = x^2$ is rotated about the $x$-axis.
Find the volume of the solid obtained by rotating the region bounded by $y = 4 - x^2$ and $y = 3$ about the line $y = 3$.
Find the volume of the solid obtained by rotating the region bounded by $y = x^3 - x$ and $y = 0$ (for $x \geq 0$) about the $y$-axis.
Hint: Solving $y = x^3 - x$ for $x$ in terms of $y$ leads to the cubic formula.
Consider the region $R$ bounded by $y = \sqrt{x}$, $y = 0$, and $x = 4$.
| Mistake | Why It Happens | Correction |
|---|---|---|
| Always using the method learned first | Habit, not strategy | Ask: "Which variable describes the region more naturally?" |
| Forgetting to change bounds when switching methods | Mixing $x$ and $y$ bounds | If switching $dx \to dy$, convert all bounds to $y$-values. |
| Not checking if inversion is feasible | Jumping into washers without thinking | Before choosing washers for vertical axis, verify that $y = f(x)$ can be solved for $x$. |
| Using shells when washers are simpler | "Shells are always better" mindset | For simple functions rotated about the $x$-axis, washers often win. |
With both methods mastered, you're ready for:
The Strip Direction Rule:
Draw your region. Draw a thin strip. Rotate it mentally:
Pick the strip direction that makes the boundaries easiest to describe.
If boundaries are given as $y = f(x)$, vertical strips (which preserve that form) are usually easier. If boundaries are given as $x = g(y)$, horizontal strips are usually easier.
| Previous | Up | Next |
|---|---|---|
| Shell Method: Other Axes | Section 5.3 | Section 5.4 |
Last updated: 2026-01-23