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The Number e

MATH162
Reference: Stewart 6.2  •  Chapter: 6  •  Section: 2

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The Number e

Why $e$ is Special

Among all possible bases for exponential functions, one stands out: the number $e \approx 2.71828$. What makes $e$ special isn't its numerical value—it's that $e^x$ is the only exponential function that is its own derivative.

This property makes $e^x$ the natural choice for modeling continuous growth and decay. Whenever something grows "at a rate proportional to its current size," the mathematics naturally leads to $e$.

The constant $e$ appears everywhere: compound interest, population models, probability distributions, physics, and engineering. Understanding why $e$ is special (not just memorizing its value) is key to understanding exponential calculus.

Prerequisite Map

This skill
The Number e

Quick Reference

Property Value/Formula
Approximate Value $e \approx 2.71828182845904...$
Defining Property $\displaystyle\lim_{h \to 0} \frac{e^h - 1}{h} = 1$
Key Derivative $\frac{d}{dx}[e^x] = e^x$
Characterization $e$ is between 2 and 3, and $e^x$ has slope 1 at $x = 0$
Natural Exponential $f(x) = e^x$ is called the natural exponential function

Key Concepts

The Search for the "Perfect" Base

When we differentiate $f(x) = b^x$ using the limit definition:

$$f'(x) = \lim_{h \to 0} \frac{b^{x+h} - b^x}{h} = \lim_{h \to 0} \frac{b^x \cdot b^h - b^x}{h} = b^x \cdot \lim_{h \to 0} \frac{b^h - 1}{h}$$

The derivative of any exponential function equals the function times a constant:

$$\boxed{\frac{d}{dx}[b^x] = b^x \cdot f'(0) \quad \text{where } f'(0) = \lim_{h \to 0} \frac{b^h - 1}{h}}$$

This constant $f'(0)$ depends on the base $b$:

Base $\displaystyle\lim_{h \to 0} \frac{b^h - 1}{h}$
$b = 2$ $\approx 0.693$
$b = 3$ $\approx 1.099$
$b = ?$ $= 1$ (this is $e$!)

Definition of $e$

$$\boxed{e \text{ is the unique number such that } \lim_{h \to 0} \frac{e^h - 1}{h} = 1}$$

Geometric meaning: The function $f(x) = e^x$ has a tangent line with slope exactly 1 at the point $(0, 1)$.

      y
      |           /
      |          / y = e^x
      |         /
      |       /
      |     /   slope = 1 at (0,1)
      |   /___
      | /  tangent line
      |/
   ---+------------------------ x
      |(0,1)

Why $e$ is Between 2 and 3

Numerical evidence:

Since the limit increases with $b$, there must be a unique $b$ between 2 and 3 where the limit equals exactly 1. This number is $e$.

Computing the Value of $e$

Decimal Places Value
2 2.72
5 2.71828
10 2.7182818285
20 2.71828182845904523536

Important: $e$ is irrational—its decimal expansion never terminates or repeats.

The Natural Exponential Function

$$\boxed{f(x) = e^x \text{ is the \textbf{natural exponential function}}}$$

Properties of $e^x$:

Why $e^x$ Being Its Own Derivative Matters

The equation $\frac{dy}{dx} = y$ (rate of change equals current value) has solution $y = Ce^x$.

Real-world meaning: When something grows at a rate proportional to itself (bacteria, investments, rumors), the mathematics naturally produces $e$.

Alternative Characterizations of $e$

The number $e$ can be defined in several equivalent ways:

$$\boxed{e = \lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n}$$

This limit arises from compound interest: if you invest $1 at 100% annual interest compounded $n$ times per year, your balance after one year approaches $e$ as $n \to \infty$.

$n$ $\left(1 + \frac{1}{n}\right)^n$
1 2
10 2.5937...
100 2.7048...
1000 2.7169...
$\to \infty$ $e = 2.71828...$

Common Mistakes

Mistake Correct Understanding
Thinking $e$ is rational $e$ is irrational (decimal never repeats)
Confusing $e$ with $e^1$ These are the same: $e = e^1 \approx 2.718$
Thinking $e^0 = e$ $e^0 = 1$ (like any base)
Using $e \approx 3$ Use $e \approx 2.718$ for estimates
Thinking other bases work Only $e^x$ equals its own derivative

Practice Problems

Level 1 Basic Calculations with $e$

Evaluate (leave answers in exact form or round to 3 decimal places): (a) $e^0$ (b) $e^1$ (c) $e^{-1}$

Thought Process

Recall that $b^0 = 1$ for any positive base, and $e^1 = e$. For $e^{-1}$, use $b^{-n} = 1/b^n$.

Show Answer

(a) $e^0 = \boxed{1}$ (any positive number raised to 0 equals 1)

(b) $e^1 = \boxed{e} \approx 2.718$

(c) $e^{-1} = \frac{1}{e} \approx \boxed{0.368}$

Level 2 Using the Compound Interest Limit

Compute $\left(1 + \frac{1}{100}\right)^{100}$ to 4 decimal places and compare to $e$.

Thought Process

Connection to the definition: This expression comes from compound interest—if you invest $1 at 100% annual interest, compounded $n$ times per year, you get $(1 + 1/n)^n$ after one year.

What to expect: As $n$ increases, this converges to $e$. With $n = 100$, we should get a good approximation but not the exact value. This shows how $e$ naturally emerges from financial mathematics.

Show Answer

$\left(1 + \frac{1}{100}\right)^{100} = (1.01)^{100} \approx \boxed{2.7048}$

Compare to $e \approx 2.7183$.

The approximation is within 0.5% of $e$. As $n \to \infty$, this approaches $e$ exactly.

Level 3 Why $e$ Isn't 2 or 3

Verify numerically that $\lim_{h \to 0} \frac{2^h - 1}{h} \neq 1$ by computing the expression for $h = 0.01$ and $h = 0.001$.

Thought Process

Compute $\frac{2^h - 1}{h}$ directly for small values of $h$. The limit should approach something less than 1.

Show Answer

For $h = 0.01$: $$\frac{2^{0.01} - 1}{0.01} = \frac{1.00696 - 1}{0.01} \approx \boxed{0.696}$$

For $h = 0.001$: $$\frac{2^{0.001} - 1}{0.001} = \frac{1.000693 - 1}{0.001} \approx \boxed{0.693}$$

The limit approaches approximately $0.693$, not 1.

Conclusion: $2^x$ does NOT equal its own derivative. The derivative of $2^x$ is approximately $0.693 \cdot 2^x$.

Level 4 Tangent Line at the Special Point

Find the equation of the tangent line to $y = e^x$ at the point where $x = 0$.

Thought Process

The tangent line at $(a, f(a))$ has equation $y - f(a) = f'(a)(x - a)$. At $x = 0$: find $f(0)$ and $f'(0)$. Remember that the defining property of $e$ is that $f'(0) = 1$ for $f(x) = e^x$.

Show Answer

At $x = 0$:

  • $f(0) = e^0 = 1$, so the point is $(0, 1)$
  • $f'(x) = e^x$, so $f'(0) = e^0 = 1$

Tangent line equation: $$y - 1 = 1(x - 0)$$ $$\boxed{y = x + 1}$$

Geometric interpretation: The tangent to $y = e^x$ at $(0, 1)$ has slope exactly 1. This is the defining property of $e$!

Level 5 The Continuous Compounding Limit

Show that $\lim_{n \to \infty} \left(1 + \frac{x}{n}\right)^n = e^x$ for any fixed real number $x$.

Hint: Let $m = n/x$ so that $n = mx$, and rewrite the expression.

Thought Process

Substitute $m = n/x$ to convert to the form $(1 + 1/m)^{m \cdot x}$. Then use the fact that $(1 + 1/m)^m \to e$ as $m \to \infty$.

Show Answer

Let $m = n/x$, so $n = mx$ and as $n \to \infty$, we have $m \to \infty$.

$$\left(1 + \frac{x}{n}\right)^n = \left(1 + \frac{x}{mx}\right)^{mx} = \left(1 + \frac{1}{m}\right)^{mx}$$

$$= \left[\left(1 + \frac{1}{m}\right)^m\right]^x$$

As $m \to \infty$: $$\lim_{m \to \infty} \left(1 + \frac{1}{m}\right)^m = e$$

Therefore: $$\lim_{n \to \infty} \left(1 + \frac{x}{n}\right)^n = e^x$$

Application: This is the formula for continuous compound interest. If you invest $P$ at annual rate $r$, compounding $n$ times per year for $t$ years:

$$A = P\left(1 + \frac{r}{n}\right)^{nt}$$

As $n \to \infty$: $A = Pe^{rt}$ (continuous compounding).

CCI-Style Conceptual Questions

Question 1: The defining property of $e$ is:

(A) $e \approx 2.718$ (B) $e^1 = e$ (C) The tangent line to $y = e^x$ at $(0, 1)$ has slope 1 (D) $e$ is irrational

Answer

(C) While all statements are true, the defining property of $e$ is that $\lim_{h \to 0} \frac{e^h - 1}{h} = 1$, which geometrically means the tangent line at $(0, 1)$ has slope 1. Options (A), (B), and (D) are consequences, not definitions.

Question 2: If $f(x) = 2^x$, then $f'(x)$ equals:

(A) $2^x$ (B) $x \cdot 2^{x-1}$ (C) $2^x \ln 2$ (D) $e^x$

Answer

(C) The derivative of $b^x$ is $b^x \ln b$. For base 2, this gives $2^x \ln 2$. Only $e^x$ equals its own derivative; for any other base, there's an extra factor.

Question 3: As $n$ increases, $\left(1 + \frac{1}{n}\right)^n$:

(A) Increases without bound (B) Approaches 1 (C) Approaches $e$ (D) Oscillates

Answer

(C) This is one of the fundamental definitions of $e$. The sequence increases but is bounded above by 3, and converges to $e \approx 2.718$.

Mastery Checklist

Mental Model

The "Just Right" Base:

Imagine trying to find an exponential function where the growth rate at $x = 0$ is exactly 100% of the current value.

This "Goldilocks property" is why $e$ appears throughout calculus and nature—it's the base where growth rate perfectly matches current size.

Continuous compounding analogy: If a bank offers 100% interest but compounds it continuously (infinitely often), $1 becomes $e \approx $2.72 after one year.

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Exponential Properties Skills Index Derivatives of Exponentials

Last updated: 2026-01-23